Modern Physics Ques 190

Passage Based Questions

Passage

The mass of a nucleus ${ } _Z^{A} X$ is less that the sum of the masses of $(A-Z)$ number of neutrons and $Z$ number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass $M$ can break into two light nuclei of masses $m _1$ and $m _2$ only if $\left(m _1+m _2\right)<M$. Also two light nuclei of masses $m _3$ and $m _4$ can undergo complete fusion and form a heavy nucleus of mass $M^{\prime}$ only if $\left(m _3+m _4\right)>M^{\prime}$. The masses of some neutral atoms are given in the table below

(2013 Adv.)

${ } _1^{1} H$ $1.007825 u$ ${ } _1^{2} H$ $2.014102 u$
${ } _3^{6} Li$ $6.01513 u$ ${ } _3^{7} Li$ $7.016004 u$
${ } _{64}^{152} Gd$ $151.919803 u$ ${ } _{82}^{206} Pb$ $205.974455 u$
${ } _1^{3} H$ $3.016050 u$ ${ } _2^{4} He$ $4.002603 u$
${ } _{30}^{70} Zn$ $69.925325 u$ ${ } _{34}^{82} Se$ $81.916709 u$
  1. The correct statement is

(a) The nucleus ${ } _3^{6} Li$ can emit an alpha particle.

(b) The nucleus ${ } _{84}^{210}$ Po can emit a proton.

(c) Deuteron and alpha particle can undergo complete fusion.

(d) The nuclei ${ } _{30}^{70} Zn$ and ${ } _{34}^{82} Se$ can undergo complete fusion.

Show Answer

Answer:

Correct Answer: 190.(c)

Solution:

Formula:

Alpha - Decay Process:

  1. (a) ${ } _3 Li^{7} \rightarrow{ } _2 He^{4}+{ } _1 H^{3}$

$ \begin{aligned} \Delta m & =\left[M _{Li}-M _{He}-M _{H^{3}}\right] \\ & =[6.01513-4.002603-3.016050] \\ & =-1.003523 u \end{aligned} $

$\Delta m$ is negative so reaction is not possible.

(b) ${ } _{84} Po^{210} \rightarrow{ } _{83} Bi^{209}+{ } _1 P^{1}$

$\Delta m$ is negative so reaction is not possible.

(c) ${ } _1 H^{2} \rightarrow{ } _2 He^{4}+{ } _3 Li^{6}$

$\Delta m$ is positive so reaction is possible.

(d) ${ } _{30} Zn^{70}+{ } _{34} Se^{82} \rightarrow{ } _{64} Gd^{152}$

$\Delta m$ is positive so reaction is not possible.



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