Modern Physics Ques 2
(a) $10 \mathrm{~mA}$
(b) $17 \mathrm{~mA}$
(c) $15 \mathrm{~mA}$
(d) $7 \mathrm{~mA}$
Show Answer
Answer:
Correct Answer: 2.( a )
Solution:
where,potential drop across $800 \Omega$ resistance $=$ potential drop across Zener diode $=5.6 \mathrm{~V}$
So, current, $i_2=\frac{V}{R}=\frac{5.6}{800}=7 \mathrm{~mA}$
Now, potential drop across $200 \Omega$ resistance
$ =9-5.6=3.4 \mathrm{~V} $
Current, $i_1=\frac{V}{R}=\frac{3.4}{200}=17 \mathrm{~mA}$
So, current, $i_2=i_1-i_2=17-7=10 \mathrm{~mA}$
BETA
