Modern Physics Ques 201
- The binding energies per nucleon for deuteron $\left({ } _1 H^{2}\right)$ and helium $\left({ } _2 He^{4}\right)$ are $1.1$ $ MeV$ and $7.0 $ $MeV$ respectively. The energy released when two deuterons fuse to form a helium nucleus $\left({ } _2 He^{4}\right)$ is ……..
$(1988,2 M)$
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Answer:
Correct Answer: 201.$(23.6$ $ MeV)$
Solution:
Formula:
- $2{ } _1 H^{2} \rightarrow{ } _2 He^{4}$
Binding energy of two deuterons,
$ E _1=2[2 \times 1.1]=4.4 $ $MeV $
Binding energy of helium nucleus,
$ \begin{aligned} E _2 & =4(7.0)=28.0 MeV \\ \therefore \quad \text { Energy released } \Delta E & =E _2-E _1 \\ & =(28-4.4) MeV=23.6 MeV \end{aligned} $
BETA
