Modern Physics Ques 217
- The output of the given logic circuit is
(Main 2019, 12 Jan I)
(a) $A \bar{B}$
(b) $\bar{A} B$
(c) $A B+\overline{A B}$
(d) $A \bar{B}+\bar{A} B$
Show Answer
Answer:
Correct Answer: 217.(a)
Solution:
Formula:
- Truth table for given circuit is
| $\boldsymbol{A}$ | $\boldsymbol{B}$ | $\boldsymbol{Y} _{\mathbf{1}}$ | $\boldsymbol{Y} _{\mathbf{2}}$ | $\boldsymbol{Y} _{\mathbf{3}}$ | $\boldsymbol{Y}$ |
|---|---|---|---|---|---|
| 0 | 0 | 1 | 1 | 1 | 0 |
| 1 | 0 | 1 | 1 | 0 | 1 |
| 0 | 1 | 1 | 1 | 1 | 0 |
| 1 | 1 | 0 | 1 | 1 | 0 |
This is the same output produced by $A \cdot \bar{B}$ gate or
So, given circuit is equivalent to Boolean expression $A \cdot \bar{B}$.
BETA
