Modern Physics Ques 218
- The circuit shown below contains two ideal diodes, each with a forward resistance of $50 $ $\Omega$. If the battery voltage is $6$ $ V$, the current through the $100 $ $\Omega$ resistance (in ampere) is
(Main 2019, 11 Jan II)
(a) $ 0.027$
(b) $ 0.020$
(c) $ 0.030$
(d) $ 0.036$
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Answer:
Correct Answer: 218.(b)
Solution:
- In this circuit, $D _1$ is forward biased and $D _2$ is reversed biased.
Resistance of $D _1$ is $50 $ $\Omega$.
$\therefore$ Net resistance of the circuit,
$ R _{\text {net }}=50+150+100=300 $ $\Omega $
$\therefore$ Current through the $100 $ $\Omega$ resistance
$ =\frac{V}{R _{\text {net }}}=\frac{6}{300}=0.020 $ $A $
BETA
