Modern Physics Ques 241
- In an $n-p-n$ transistor circuit, the collector current is $10$ $ mA$. If $90 \%$ of the electrons emitted reach the collector
$(1992,2 M)$
(a) the emitter current will be $9 $ $mA$
(b) the emitter current will be $11 $ $mA$
(c) the base current will be $1 $ $mA$
(d) the base current will be $-1 $ $mA$
Show Answer
Answer:
Correct Answer: 241.(b,c)
Solution:
Formula:
- Given : $i _c=10$ $ mA=(0.9) i _e \quad$ [Given that $i _c$ is $90 \%$ of $i _e$ ]
$\therefore \quad i _e=\frac{10}{0.9}$ $ mA \approx 11 $ $mA $
$\text { and } i _b=i _e-i _c=(11-10) $ $mA=1$ $ mA$
BETA
