Modern Physics Ques 284

  1. ${ }^{22} Ne$ nucleus, after absorbing energy, decays into two $\alpha$-particles and an unknown nucleus. The unknown nucleus is

$(1999,2 M)$

(a) nitrogen

(b) carbon

(c) boron

(d) oxygen

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Answer:

Correct Answer: 284.(b)

Solution:

Formula:

Alpha - Decay Process:

  1. Atomic number of neon is $10$ .

By the emission of two $\alpha$-particles, atomic number will be reduced by $4$ . Therefore, atomic number of the unknown element will be $Z=10-4=6$

Similarly, mass number of the unknown element will be

$ A=22-2 \times 4=14 $

Unknown nucleus is carbon ( $A=14, Z=6$ ).



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