Modern Physics Ques 285

  1. If elements with principal quantum number $n>4$ were not allowed in nature, the number of possible elements would be

$(1983,1 M)$

(a) $60$

(b) $32$

$4$

(d) $64$

Show Answer

Answer:

Correct Answer: 285.(a)

Solution:

  1. The maximum number of electrons in an orbit are $2 n^{2}$. If $n>4$, it is not allowed, then the number of maximum electrons that can be in first four orbit are :

$ 2(1)^{2}+2(2)^{2}+2(3)^{2}+2(4)^{2}=2+8+18+32=60 $

Therefore, possible elements can be $60$ .



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