Modern Physics Ques 52
- In the Bohr model of the hydrogen atom, the ratio of the kinetic energy to the total energy of the electron in a quantum state $n$ is………
(1992, 1M)
Show Answer
Answer:
Correct Answer: 52.$(-1)$
Solution:
Formula:
- Kinetic energy of an electron in $n$th orbit of hydrogen atom is $K=\frac{m e^{4}}{8 \varepsilon _0^{2} h^{2} n^{2}}$ and total energy of electron in $n$th orbit is
$ E=-\frac{m e^{4}}{8 \varepsilon _0^{2} h^{2} n^{2}}, \frac{K}{E}=-1 $
or
$ K=-E $
BETA
