Properties Of Matter Ques 30

  1. The adjacent graph shows the extension $(\Delta l)$ of a wire of length $1 m$ suspended from the top of a roof at one end and with a load $w$ connected to the other end. If the cross-sectional area of the wire is $10^{-6} m^{2}$, calculate from the graph the Young’s modulus of the material of the wire.

(2003, 2M)

(a) $2 \times 10^{11} N / m^{2}$

(b) $2 \times 10^{-11} N / m^{2}$

(c) $3 \times 10^{12} N / m^{2}$

(d) $2 \times 10^{13} N / m^{2}$

Show Answer

Answer:

Correct Answer: 30.(a)

Solution:

  1. $\Delta l=\left(\frac{l}{Y A}\right) \cdot w$

i.e. graph is a straight line passing through origin (as shown in question also), the slope of which is $\frac{l}{Y A}$.

$$ \begin{array}{rlrl} \therefore \quad & \text { Slope } & =\left(\frac{l}{Y A}\right) \\ \therefore \quad & Y & =\left(\frac{l}{A}\right)\left(\frac{1}{\text { slope }}\right)=\left(\frac{1.0}{10^{-6}}\right) \frac{(80-20)}{(4-1) \times 10^{-4}} \\ & =2.0 \times 10^{11} N / m^{2} \end{array} $$



Table of Contents

sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें