Simple Harmonic Motion Ques 1
- A mass $M$ attached to a spring oscillates with a period of $2 \mathrm{~s}$. If the mass is increased by $2 \mathrm{~kg}$ the period increases by one sec. Find the initial mass $M$ assuming that Hooke’s law is obeyed.
(1979)
Show Answer
Answer:
Correct Answer: 1.$M=16 \mathrm{~kg}$
Solution:
$ \begin{array}{rlrl} T =2 \pi \sqrt{\frac{M}{K}} \text { or } T \propto \sqrt{M}, \frac{T_2}{T_1}=\sqrt{\frac{M_2}{M_1}} \\ \therefore \quad \frac{3}{2}=\sqrt{\frac{M+2}{M}} \end{array} $
Solving the equation (i), we get, $M=1.6 \mathrm{~kg} $.