Simple Harmonic Motion Ques 33
- A spring of force constant $k$ is cut into two pieces such that one piece is double the length of the other. Then, the long piece will have a force constant of
(1999, 2M)
(a) $\frac{2}{3} k$
(b) $\frac{3}{2} k$
(c) $3 k$
(d) $6 k$
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Answer:
Correct Answer: 33.(b)
Solution:
Formula:
- $l _1=2 l _2 \quad \therefore \quad l _1=\frac{2}{3} l$
$$ \therefore \quad k _1=\frac{3}{2} k $$
Force constant $k \propto \frac{1}{\text { length of spring }}$
BETA
