JEE Main 12 Jan 2019 Evening Question 15
Question: Given:
(i) $ {C _{(graphite)}}+{O _{2(g)}}\to C{O _{2(g)}};{\Delta_r}H^{o}=x,kJ,mol^{-1}$
(ii) $ {C _{(graphite)}}+\frac{1}{2}{O _{2(g)}}\to CO _{(g)}; $ $ {\Delta_r}H^{o}=yk,J,mol^{-1}$
(iii) $ CO_{(g)}+\frac{1}{2}O_{2(g)}\to CO_{2(g)};\Delta_rH^{o}=z,kJ,mol^{-1}$
Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct? [JEE Main Online Paper Held On 12-Jan-2019 Evening]
Options:
A) $ z=x+y $
B) $ x=y-z $
C) $ x=y+z $
D) $ y=2zx $
Show Answer
Answer:
Correct Answer: C
Solution:
- By adding equation (ii) and (iii), we get $ C(graphite)+O_{2(g)}\to CO_{2(g)}}, $ i.e., $ x=y+z $
BETA
