Center Of Mass Momentum And Collision Question 5
Question 5 - 30 January - Shift 2
A machine gun of mass $10 kg$ fires $20 g$ bullets at the rate of 180 bullets per minute with a speed of $100 m s^{-1}$ each. The recoil velocity of the gun is :
(1) $0.02 m / s$
(2) $2.5 m / s$
(3) $1.5 m / s$
(4) $0.6 m / s$
Show Answer
Answer: (4)
Solution:
Formula: Conservation of Momentum
$20 \times 10^{-3} \times \frac{180}{60} \times 100=10 V$
$\Rightarrow v=0.6 m / s$
BETA
