Center Of Mass Momentum And Collision Question 9
Question 9 - 01 February - Shift 2
Figures (a), (b), (c) and (d) show variation of force with time.
The impulse is highest in figure.
(1) Fig (c)
(2) Fig (b)
(3) Fig (a)
(4) Fig (d)
Show Answer
Answer: (2)
Solution:
Formula: Impulse
Impulse $=$ Area under $F=t$ curve
(a) $\frac{1}{2} \times 1 \times 0.5=\frac{1}{4}$ N.s
(b) $0.5 \times 2=1$ N.s (maximum)
(c) $\frac{1}{2} \times 1 \times 0.75=\frac{3}{8}$ N.s
(d) $\frac{1}{2} \times 2 \times 0.5=\frac{1}{2}$ N.s
BETA
