Jee Main 2024 27 01 2024 Shift 1 - Question2
Question 2
The vertices of a triangle $A B C$ are $A(1,2), B(-3,4)$, $C(5,8)$, then orthocentre of $\triangle A B C$ is
(1) $\left(\frac{2}{3}, 1\right)$
(2) $\left(-\frac{7}{3}, 2\right)$
(3) $(2,3)$
(4) $\left(\frac{3}{2}, 1\right)$
Show Answer
Answer: (4)
Solution:
Intersection of $A D$ and $B E: H\left(\frac{3}{2}, 1\right)$
BETA
