Jee Main 2024 29 01 2024 Shift 2 - Question3

Answer: (1)

Solution:

Set $A={1,2,3,4}$

For reflexive relation

We need to have $(1,1),(2,2),(3,3),(4,4)$.

For symmetry,

$(1,3) \in A$

So $(3,1)$ should be added

And $(1,2) \in A$

So $(2,1)$ should be added

set has become ${(1,1),(2,2),(3,3),(4,4),(1,3),(3,1),(1,2),(2,1)}$

Now $(3,1) \in A$

$(1,2) \in A$

So $(3,2)$ should be added (for transitivity)

Then $(2,3)$ should be added (for symmetric)

So set becomes a set

${(1,1),(2,2),(3,3),(4,4),(1,3),(3,1),(1,2),(2,1),(3,2),(2,3)}$

At least 8 elements are added