Jee Main 2024 30 01 2024 Shift1 - Question11
Question 11
A line passes through $(9,0)$, making angle $30^{\circ}$ with positive direction of $x$-axis. It is rotated by angle of $15^{\circ}$ with respect to the original line. Then one of the equation of new line is
(1) $y=(2+\sqrt{3})(x-9)$
(2) $y=(2-\sqrt{3})(x-9)$
(3) $y=2(x-9)$
(4) $y=-(x-9)$
Show Answer
Answer: (2)
Solution:
$Eq^{n}: y-0=\tan 15^{\circ}(x-9) \Rightarrow y=(2-\sqrt{3})(x-9)$
$Eq^{n}: y-0=\tan 45^{\circ}(x-9) \Rightarrow y=(x-9)$
Option (B) is correct
BETA
