Jee Main 2024 30 01 2024 Shift1 - Question14
Question 14
Given set $S={0,1,2,3, \ldots . ., 10}$. If a random ordered pair $(x, y)$ of elements of $S$ is chosen, then find probability that $|x-y|>5$
(1) $\frac{30}{121}$
(2) $\frac{31}{121}$
(3) $\frac{62}{121}$
(4) $\frac{64}{121}$
Show Answer
Answer: (1)
Solution:
If $x=0, y=6,7,8,9,10$
If $x=1, y=7,8,9,10$
If $x=2, y=8,9,10$
If $x=3, y=9,10$
If $x=4, y=10$
If $x=5, y=$ no possible value
Total possible ways $=(5+4+3+2+1) \times 2$
$$ =30 $$
Required probability $=\frac{30}{11 \times 11}=\frac{30}{121}$
BETA
