Jee Main 2024 30 01 2024 Shift1 - Question18

Question 18

For the following data table

$x _i$$f _i$
$0-4$2
$4-8$4
$8-12$7
$12-16$8
$16-20$6

Find the value of $20 M$ (where $M$ is median of the data)

Show Answer

Answer: (245)

Solution:

$x _i$$f _i$c.f.
$0-4$22
$4-8$46
$8-12$713
$12-16$821
$16-20$627

$$ \begin{array}{r} N=\sum f=27 \\ \left(\frac{N}{2}\right)=\frac{27}{2}=13.5 \end{array} $$

So, we have median lies in the class $12-16$

$l _1=12, f=8, h=4$, c.f. $=13$

So, here we apply formula

$$ \begin{aligned} M & =I _1+\frac{\frac{N}{2}-c . f .}{f} \times h=12+\frac{13.5-13}{8} \times 4 \\ & =12+\frac{.5}{2} \end{aligned} $$

$M=\frac{24.5}{2}=12.25$

$$ 20 M=20 \times 12.25 $$

$$ =245 $$



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