Center Of Mass Momentum And Collision Question 1
Question 1 - 2024 (01 Feb Shift 1)
A simple pendulum of length $1 m$ has a wooden bob of mass $1 kg$. It is struck by a bullet of mass $10^{-2} kg$ moving with a speed of $2 \times 10^{2} ms^{-1}$. The bullet gets embedded into the bob. The height to which the bob rises before swinging back is. (use $g=10 m / s^{2}$ )
(1) $0.30 m$
(2) $0.20 m$
(3) $0.35 m$
(4) $0.40 m$
Show Answer
Answer: (2)
Solution:
$mu=(M+m) V$
$10^{-2} \times 2 \times 10^{2} \cong 1 \times V$
$V \cong 2 m / s$
$h=\frac{V^{2}}{2 g}=0.2 m$
BETA
