Two particles each of mass $2 kg$ are placed as shown in $x y$ plane. If the distance of centre of mass from origin is $\frac{4 \sqrt{2}}{x}$, find $x$
$\vec{r} _{cm}=-2 \hat{i}+2 \hat{j}$
$ \therefore \quad r=2 \sqrt{2} $
$x=2$
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