Jee Main 2024 01 02 2024 Shift 1 - Question19
Question 19
The length of a seconds pendulum if it is placed at height $2 R$ ( $R$ : radius of earth) is $\frac{10}{x \pi^{2}}$ metres. Find $x$.
Show Answer
Answer: (9)
Solution:
$T=2 \pi \sqrt{\frac{l}{g}}$
$ \begin{alignedat} & \Rightarrow \quad 2=2 \pi \sqrt{\frac{l}{g _0 / 9}} \\ & \Rightarrow \quad 2=2 \pi \times 3 \sqrt{\frac{g}{10}} \\ & \Rightarrow \quad \frac{I}{10}=\frac{1}{9 \pi^{2}} \\ & \Rightarrow \quad I=\frac{10}{9 \pi^{2}} m \end{aligned} $
BETA
