Jee Main 2024 01 02 2024 Shift 1 - Question2
Question 2
A vernier caliper has 10 main scale divisions coinciding with 11 vernier scale divisions. 1 main scale division equals $5 mm$. The least count of the device is
(1) $\frac{1}{2} mm$
(2) $\frac{5}{12} mm$
(3) $\frac{5}{11} mm$
(4) $0.3 mm$
Show Answer
Answer: (3)
Solution:
$10 M=11 V$
$ \begin{aligned} \Rightarrow 1 V & =\frac{10}{11} \times 5 mm \\ \Rightarrow LC & =|M-V| \\ & =\frac{5}{11} mm \end{aligned} $
BETA
