Jee Main 2024 29 01 2024 Shift 1 - Question14
Question 14
In the voltage regulator circuit shown below, the reverse breakdown voltage of zener diode is $3.0 V$. Find the current through zener diode.
(1) $7 mA$
(2) $1.5 mA$
(3) $5.5 mA$
(4) $10 mA$
Show Answer
Answer: (3)
Solution:
$\text { battery }=\frac{10-3}{1000}=7 \text{ mA}$
$2 k \Omega=\frac{3}{2000}=1.5 mV$
$i _z=(7-1.5) mA$
$=5.5 mA$
BETA
