Jee Main 2024 29 01 2024 Shift 1 - Question15
Question 15
Consider the circuit shown. Galvanometer resistance is $10 \Omega$ and current through galvanometer is $3 mA$. Find the resistance of shunt.
(1) $10^{-3} \Omega$
(2) $7.5 \times 10^{-3} \Omega$
(3) $6.75 \times 10^{-3} \Omega$
(4) $3.75 \times 10^{-3} \Omega$
Show Answer
Answer: (4)
Solution:
Since $G$ and $S$ are in parallel
$ \begin{aligned} & \Rightarrow V _G=V _S \\ & \Rightarrow 3 mA \times 10 = 30 mA = 8 A \times R_S \ & \Rightarrow R_S=3.75,\mathrm{m\Omega} \end{aligned} $
BETA
