Jee Main 2024 29 01 2024 Shift 1 - Question22
Question 22
Voltage and resistance for a resistor are measured as $V=200 \pm 5$ volts and $R=20 \pm 0.2 \Omega$. The percentage error in current $I=\frac{V}{R}$ is $x$. Find the value of $10 x$
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Answer: (35)
Solution:
$%$ error $=\left(\frac{d V}{V}+\frac{d R}{R}\right) \times 100$
$\begin{aligned} & =\left(\frac{5}{200}+\frac{0.2}{20}\right) \times 100 \\ & =3.5 \end{aligned}$
BETA
