Jee Main 2024 29 01 2024 Shift 1 - Question5
Question 5
de-Broglie wavelength of a proton and an electron is same. The ratio of kinetic energy of electron to that of proton is
(1) 1
(2) 1835
(3) $\frac{1}{1867}$
(4) 933.5
Show Answer
Answer: (2)
Solution:
$\frac{h}{p _1}=\frac{h}{p _2}$
$ \begin{aligned} & \Rightarrow \sqrt{2 m _1 k _1}=\sqrt{2 m _2 k _2} \\ & \Rightarrow \frac{k _2}{k _1}=\frac{m _1}{m _2}=1835 \end{aligned} $
BETA
