Jee Main 2024 29 01 2024 Shift 1 - Question8
Question 8
A square loop of resistance $16 \Omega$ is connected with battery of $9 V$ and internal resistance of $1 \Omega$. In steady state, find energy stored in capacitor of capacity $C=4$ $\mu F$ as shown (at steady state current divides symmetrically)
(1) $51.84 \mu J$
(2) $12.96 \mu J$
(3) $25.92 \mu J$
(4) $103.68 \mu J$
Show Answer
Answer: (3)
Solution:
Equivalent circuit
$i=\frac{9}{4+1}=1.8 A$
$\Rightarrow \frac{i}{2}=0.9 A$
$\left(V _P-V _Q\right)=0.9 \times 6-0.9 \times 2$
$V _C=3.6 V$
$U=\frac{1}{2} C V^{2}=\frac{1}{2} \times 4 \times 3.6 \times 3.6 \mu J$
$=25.92 \mu J$
BETA
