Jee Main 2024 31 01 2024 Shift 1 - Question16
Question 16
In YDSE, intensity at two sources are in ratio of $1: 9$. If sources are coherent, then intensity at central point is $I _1$ and if sources are coherent (and phase differs by $60^{\circ}$ ), then intensity at central than is $I _2$, then $\frac{I _1}{I _2}$ is
(1) $\frac{10}{13}$
(2) $\frac{5}{13}$
(3) $\frac{8}{13}$
(4) $\frac{7}{11}$
Show Answer
Answer: (1)
Solution:
$l_1=1+9=10$
$I _2=1+9+2 \sqrt{9} \cos 60^{\circ}=13$
$\frac{l _1}{l _3}=\frac{10}{13}$
BETA
