Jee Main 2024 31 01 2024 Shift 1 - Question18
Question 18
A ball dropped from height $H$ rebounds upto height $h$ after colliding with horizontal surface. If coefficient of restitution for collision is $e=\frac{1}{2}$ then $\frac{H}{h}$ shall be
Show Answer
Answer: (4)
Solution:
Defn of $e=\frac{1}{2}=\frac{\sqrt{2 g h}}{\sqrt{2 g H}}$
$ \begin{aligned} & \frac{1}{4}=\frac{h}{H} \\ \Rightarrow & 4 \end{aligned} $
BETA
