Jee Main 2024 31 01 2024 Shift 1 - Question21
Question 21
Mass defect in a nuclear reaction is $0.4 U$. The $Q$ value of the reaction is $\frac{x}{10} MeV$, find $x$. Take $1 U=$ 930.5 MeV/c ${ }^{2}$
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Answer: (372.2)
Solution:
$\phi=\left[930.5 \times 0.4 MeV / c^{2}\right] \times c^{2}$
$=372.2 MeV$





