Jee Main 2024 31 01 2024 Shift 1 - Question4
Question 4
4 identical particles of mass $m$ each are placed at 4 corners of a square. The gravitational force exerted on one of the mass by other masses is $\left[\frac{2 \sqrt{2}+1}{32}\right] \frac{G m^{2}}{l^{2}}$. The side length of the square is :
(1) $2/
(2) $4/
(3) $\frac{1}{2}$
$I$
Show Answer
Answer: (2)
Solution:
$ \begin{alignedat} & \frac{G m}{a^{2}} \\ \Rightarrow F _{\text {Net }} & =\frac{G m^{2}}{a^{2}}\left[\frac{1}{2}+\sqrt{2}\right] \\ & =\frac{2 \sqrt{2}+1}{2} \frac{G m^{2}}{a^{2}} \\ \Rightarrow 2 a^{2} & =32 l^{2} \\ \Rightarrow a & =4 l \end{aligned} $
BETA
