Jee Main 2024 31 01 2024 Shift 1 - Question8
Question 8
An artillery of mass $M _1$, fires a shell of mass $M _2$. At the time of firing the ratio of kinetic energy is
(1) $\frac{M _2}{M _1}$
(2) $\frac{M _1+M _2}{M _1}$
(3) $\frac{M _1+M _2}{M _2}$
(4) $\frac{M _1}{M _1+M _2}$
Show Answer
Answer: (1)
Solution:
By conservation of momentum
$P _1=-P _2$
$\frac{K _1}{K _2}=\frac{P _1^{2}}{2 M _1} \times \frac{2 M _2}{P _2^{2}}=\frac{M _2}{M _1}$
BETA
