Jee Main 2024 31 01 2024 Shift 2 - Question1
Question 1
For the block shown, $F _1$ is the minimum force required to move block upwards and $F _2$ is the minimum force required to prevent it from slipping, find $\left|\vec{F} _1-\vec{F} _2\right|$
(1) $50 \sqrt{3} N$
(2) $5 \sqrt{3} N$
(3) $25 \sqrt{3} N$
(4) $\frac{5 \sqrt{3}}{2} N$
Show Answer
Answer: (2)
Solution:
$f _K=\mu m g \cos \theta$
$ \begin{aligned} & =0.1 \times \frac{50 \times \sqrt{3}}{2} \\ & =2.5 \sqrt{3} N \end{aligned} $
$F _1=m g \sin \theta+f _K$
$ =25+2.5 \sqrt{3} $
$F _2=m g \sin \theta-f _K$
$ =25-2.5 \sqrt{3} $
$\therefore F _1-F _2=5 \sqrt{3} N$
BETA
