JEE PYQ: Aldehydes And Ketones Question 18
Question 18 - 2020 (04 Sep Shift 2)
$\text{CH}_2=\text{CH}-\text{CHO} \xrightarrow{\text{(i) NaBH}_4, \text{(ii) SOCl}_2}$ [A] $\xrightarrow{\text{Anhy. AlCl}_3}$ [B] $\xrightarrow{\text{DBr}}$ [C]
(1). (Cyclohexane derivative with Br and D)
(2). (Option 2 arrangement)
(3). (Option 3 arrangement)
(4). (Option 4 arrangement)
Show Answer
Answer: (1)
Solution
NaBH$_4$ reduces CHO to CH$_2$OH. SOCl$_2$ gives allyl chloride. Friedel-Crafts with benzene gives allylbenzene. DBr adds by Markovnikov rule.
BETA
