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$\text{C}_6\text{H}_5\text{COCH}_2\text{Br} \xrightarrow{\text{NaBH}_4/\text{MeOH, 25}^\circ\text{C}}$ ?
(1). (PhCH(OH)CH$_2$Br)
(2). (PhCH(OH)CH$_2$OMe)
(3). (Styrene oxide)
(4). (Phenyloxirane)
NaBH$_4$ reduces C=O to CHOH. In MeOH, Br is displaced by OMe. Product: PhCH(OH)CH$_2$OMe.
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