JEE PYQ: Aromatic Compounds Question 3
Question 3 - 2021 (25 Feb Shift 1)
Compound(s) which will liberate carbon dioxide with sodium bicarbonate solution is/are:
A = aminophenol, B = benzoic acid ($\text{C}_6\text{H}_5\text{COOH}$), C = 2,4-dinitrophenol
(1) B and C only
(2) B only
(3) A and B only
(4) C only
Show Answer
Answer: (1)
Solution
Compounds more acidic than $\text{H}_2\text{CO}_3$ give $\text{CO}_2$ on reaction with $\text{NaHCO}_3$. Benzoic acid and 2,4-dinitrophenol (picric acid) are both more acidic than $\text{H}_2\text{CO}_3$.
BETA
