JEE PYQ: Atomic Structure Question 29
Question 29 - 2019 (08 Apr Shift 1)
The quantum numbers of four electrons are given. The correct order of their increasing energies:
I. $n=4, l=2, m_l=-2, m_s=-1/2$ II. $n=3, l=2, m_l=1, m_s=+1/2$ III. $n=4, l=1, m_l=0, m_s=+1/2$ IV. $n=3, l=1, m_l=1, m_s=-1/2$
(1). (IV < III < II < I)
(2). (I < II < III < IV)
(3). (IV < II < III < I)
(4). (I < III < II < IV)
Show Answer
Answer: (3)
Solution
Using $(n+\ell)$ rule: IV(3p, 4) < II(3d, 5) < III(4p, 5) < I(4d, 6).
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