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What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25, in its aqueous solution?
(1). (5.92)
(2). (5)
(3). (zero)
(4). (5.26)
Mn$^{2+}$: [Ar]3d$^5$, 5 unpaired electrons. $\mu = \sqrt{5(5+2)} = \sqrt{35} = 5.92$ BM.
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