JEE PYQ: Atomic Structure Question 43
Question 43 - 2019 (11 Jan Shift 2)
The de Broglie wavelength ($\lambda$) associated with a photoelectron varies with the frequency ($\nu$) of the incident radiation as:
(1). ($\lambda \propto \frac{1}{(\nu - \nu_0)^{1/2}}$)
(2). ($\lambda \propto \frac{1}{(\nu - \nu_0)^{1/4}}$)
(3). ($\lambda \propto \frac{1}{(\nu - \nu_0)^{3/2}}$)
(4). ($\lambda \propto \frac{1}{(\nu - \nu_0)^{1/2}}$)
Show Answer
Answer: (4)
Solution
$v \propto (\nu - \nu_0)^{1/2}$, therefore $\lambda \propto \frac{1}{(\nu - \nu_0)^{1/2}}$.
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