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What is the work function of the metal if light of wavelength 4000 $\AA$ generates photoelectrons of velocity $6 \times 10^5$ m s$^{-1}$?
(1). (0.9 eV)
(2). (3.1 eV)
(3). (2.1 eV)
(4). (4.0 eV)
$E = \frac{hc}{\lambda} = 3.1$ eV. $KE = \frac{1}{2}mv^2 = 1$ eV. Work function $= 3.1 - 1 = 2.1$ eV.
BETA
