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In the ground state of atomic Fe(Z = 26), the spin-only magnetic moment is ____ $\times 10^{-1}$ BM. (Round off to the Nearest Integer).
[$\sqrt{3} = 1.73$, $\sqrt{2} = 1.41$]
Fe: [Ar]4s$^2$3d$^6$, 4 unpaired e$^-$. $\mu = \sqrt{24} = 4.89$ BM $= 48.9 \times 10^{-1}$. Answer = 49.
BETA
