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JEE PYQ: Biomolecules And Polymers Question 5

Question 5 - 2021 (17 Mar Shift 2)

$\text{C}{12}\text{H}{22}\text{O}_{11} + \text{H}_2\text{O} \xrightarrow{\text{Enzyme A}} \text{C}6\text{H}{12}\text{O}_6 + \text{C}6\text{H}{12}\text{O}_6$ Sucrose $\longrightarrow$ Glucose + Fructose

$\text{C}6\text{H}{12}\text{O}_6 \xrightarrow{\text{Enzyme B}} 2\text{C}_2\text{H}_5\text{OH} + 2\text{CO}_2$ Glucose

In the above reactions, the enzyme A and enzyme B respectively are:

(1) Amylase and Invertase

(2) Invertase and Amylase

(3) Invertase and Zymase

(4) Zymase and Invertase

Show Answer

Answer: (3)

Solution

$\text{C}{12}\text{H}{22}\text{O}_{11} + \text{H}_2\text{O} \xrightarrow{\text{Invertase}} \text{C}6\text{H}{12}\text{O}_6 + \text{C}6\text{H}{12}\text{O}_6$. $\text{C}6\text{H}{12}\text{O}_6 \xrightarrow{\text{Zymase}} 2\text{C}_2\text{H}_5\text{OH} + 2\text{CO}_2$.


Learning Progress: Step 5 of 65 in this series