JEE PYQ: Biomolecules And Polymers Question 5
Question 5 - 2021 (17 Mar Shift 2)
$\text{C}{12}\text{H}{22}\text{O}_{11} + \text{H}_2\text{O} \xrightarrow{\text{Enzyme A}} \text{C}6\text{H}{12}\text{O}_6 + \text{C}6\text{H}{12}\text{O}_6$ Sucrose $\longrightarrow$ Glucose + Fructose
$\text{C}6\text{H}{12}\text{O}_6 \xrightarrow{\text{Enzyme B}} 2\text{C}_2\text{H}_5\text{OH} + 2\text{CO}_2$ Glucose
In the above reactions, the enzyme A and enzyme B respectively are:
(1) Amylase and Invertase
(2) Invertase and Amylase
(3) Invertase and Zymase
(4) Zymase and Invertase
Show Answer
Answer: (3)
Solution
$\text{C}{12}\text{H}{22}\text{O}_{11} + \text{H}_2\text{O} \xrightarrow{\text{Invertase}} \text{C}6\text{H}{12}\text{O}_6 + \text{C}6\text{H}{12}\text{O}_6$. $\text{C}6\text{H}{12}\text{O}_6 \xrightarrow{\text{Zymase}} 2\text{C}_2\text{H}_5\text{OH} + 2\text{CO}_2$.