JEE PYQ: Biomolecules And Polymers Question 58
Question 58 - 2019 (11 Jan Shift 1)
The polymer obtained from the following reactions is:
$\text{HOOC}-(\text{CH}_2)_4-\text{NH}_2 \xrightarrow{(i) \text{ NaNO}_2/\text{H}_3\text{O}^+}$ $\xrightarrow{(ii) \text{ Polymerisation}}$
(1) $-[\overset{\text{O}}{\text{C}}-(\text{CH}_2)_4-\overset{\text{H}}{\text{N}}]-_n$
(2) $-[\text{HN}-\overset{\text{O}}{\text{C}}-(\text{CH}_2)_4-\overset{\text{O}}{\text{C}}-\overset{\text{H}}{\text{N}}]-_n$
(3) $-[\text{O}-(\text{CH}_2)_4-\overset{\text{O}}{\text{C}}]-_n$
(4) $-[\overset{\text{O}}{\text{C}}-(\text{CH}_2)_4-\text{O}]-_n$
Show Answer
Answer: (3)
Solution
$\text{NaNO}_2/\text{H}_3\text{O}^+$ converts $-\text{NH}_2$ to $-\text{OH}$, giving 5-hydroxypentanoic acid. Polymerisation gives polyester $-[\text{O}-(\text{CH}_2)_4-\overset{\text{O}}{\text{C}}]-_n$.
BETA
