JEE PYQ: Biomolecules And Polymers Question 60
Question 60 - 2019 (11 Jan Shift 2)
The homopolymer formed from 4-hydroxy-butanoic acid is:
(1) $-[\text{O}-\text{C}(\text{CH}_2)_3-\text{O}]-_n$
(2) $-[\text{O}-\text{C}(\text{CH}_2)_2-\overset{\text{O}}{\text{C}}]-_n$
(3) $-[\text{O}-\text{C}-(\text{CH}_2)_2-\text{C}-\text{O}]-_n$
(4) $-[\overset{\text{O}}{\text{C}}(\text{CH}_2)_3-\text{O}]-_n$
Show Answer
Answer: (4)
Solution
4-Hydroxybutanoic acid undergoes self-condensation polymerisation to form polyester: $-[\overset{\text{O}}{\text{C}}-(\text{CH}_2)_3-\text{O}]-_n$.
BETA
