JEE PYQ: Biomolecules And Polymers Question 9
Question 9 - 2021 (24 Feb Shift 1)
Match List I with List II.
| List I (Monomer Unit) | List II (Polymer) |
|---|---|
| (a) Caprolactum | (i) Natural rubber |
| (b) 2-Chloro-1,3-butadiene | (ii) Buna-N |
| (c) Isoprene | (iii) Nylon 6 |
| (d) Acrylonitrile | (iv) Neoprene |
(1) (a) $\to$ (iii), (b) $\to$ (iv), (c) $\to$ (i), (d) $\to$ (ii)
(2) (a) $\to$ (i), (b) $\to$ (ii), (c) $\to$ (iii), (d) $\to$ (iv)
(3) (a) $\to$ (ii), (b) $\to$ (i), (c) $\to$ (iv), (d) $\to$ (iii)
(4) (a) $\to$ (iv), (b) $\to$ (iii), (c) $\to$ (ii), (d) $\to$ (i)
Show Answer
Answer: (1)
Solution
Polymer of caprolactam is Nylon-6. Polymer of 2-chloro-1,3-butadiene is Neoprene. Polymer of isoprene is Natural rubber. Polymer of acrylonitrile and 1,3-butadiene is Buna-N.
BETA
