JEE PYQ: Chemical Equilibrium Question 12
Question 12 - 2020 (04 Sep Shift 2)
If the equilibrium constant for $\text{A} \rightleftharpoons \text{B} + \text{C}$ is $K_{\text{eq}}^{(1)}$ and that of $\text{B} + \text{C} \rightleftharpoons \text{P}$ is $K_{\text{eq}}^{(2)}$, the equilibrium constant for $\text{A} \rightleftharpoons \text{P}$ is:
(1) $K_{\text{eq}}^{(1)} / K_{\text{eq}}^{(2)}$
(2) $K_{\text{eq}}^{(2)} - K_{\text{eq}}^{(1)}$
(3) $K_{\text{eq}}^{(1)} + K_{\text{eq}}^{(2)}$
(4) $K_{\text{eq}}^{(1)} \cdot K_{\text{eq}}^{(2)}$
Show Answer
Answer: (4) $K_{\text{eq}}^{(1)} \cdot K_{\text{eq}}^{(2)}$
Solution
Adding the two reactions: A $\rightleftharpoons$ P. $K_{overall} = K_{\text{eq}}^{(1)} \cdot K_{\text{eq}}^{(2)}$.
BETA
