JEE PYQ: Chemical Equilibrium Question 15
Question 15 - 2020 (06 Sep Shift 1)
For the reaction $\text{Fe}_2\text{N}(s) + \frac{3}{2}\text{H}_2(g) \rightleftharpoons 2\text{Fe}(s) + \text{NH}_3(g)$
(1) $K_c = K_p(RT)$
(2) $K_c = K_p(RT)^{-1/2}$
(3) $K_c = K_p(RT)^{1/2}$
(4) $K_c = K_p(RT)^{3/2}$
Show Answer
Answer: (3) $K_c = K_p(RT)^{1/2}$
Solution
$\Delta n_g = 1 - 3/2 = -1/2$. $K_p = K_c(RT)^{-1/2}$, so $K_c = K_p(RT)^{1/2}$.
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