JEE PYQ: Chemical Equilibrium Question 19
Question 19 - 2020 (08 Jan Shift 1)
The stoichiometry and solubility product of a salt with the solubility curve given below is, respectively:
[Graph shows [Y]/mM vs [X]/mM: at [X] = 1 mM, [Y] = 2 mM]
(1) $\text{X}_2\text{Y}$, $2 \times 10^{-9}$ M$^3$
(2) $\text{XY}_2$, $4 \times 10^{-9}$ M$^3$
(3) $\text{XY}_2$, $1 \times 10^{-9}$ M$^3$
(4) $\text{XY}$, $2 \times 10^{-6}$ M$^3$
Show Answer
Answer: (2) $\text{XY}_2$, $4 \times 10^{-9}$ M$^3$
Solution
Salt is $\text{XY}2$. $K{sp} = [\text{X}][\text{Y}]^2 = (10^{-3})(2 \times 10^{-3})^2 = 4 \times 10^{-9}$ M$^3$.
BETA
